Let the cost of 1 ribeye steak dinner = x
The cost of 1 salmon dinner = y
Then,
11x + 18y = 592.29 (1)
16x + 6y = 580.56 (2)
Multiplying the second equation by 3, we get,
48x + 18y = 1741.68 (3)
(3) - (1) gives
37x = 1149.39
x = 31.06
Substituting the value for x in (1), we get,
11(31.06) + 18y = 592.29
341.66 + 18y = 592.29
18y = 250.63
y = 13.92
Hence, the cost of ribeye steak dinner = 31.06 and the cost of grilled salmon dinner = 13.92.
Using <u>probability distribution concepts</u>, the correct option is:
-
C. the sum of the probabilities is not 1.00
- In a probability distribution, the <u>sum of all probabilities has to be equals to 1</u>.
In this problem, the probabilities are: 0.25, 0.45, 0, 0.35.
Their sum is:
Since the <u>sum is not 1</u>, the correct option is:
- C. the sum of the probabilities is not 1.00
For more on <u>probability distribution concepts</u>, you can check brainly.com/question/24802582
Each number in the sum is even, so we can remove a factor of 2.
2 + 4 + 6 + 8 + ... + 78 + 80 = 2 (1 + 2 + 3 + 4 + ... + 39 + 40)
Use whatever technique you used in (a) and (b) to compute the sum
1 + 2 + 3 + 4 + ... + 39 + 40
With Gauss's method, for instance, we have
S = 1 + 2 + 3 + ... + 38 + 39 + 40
S = 40 + 39 + 38 + ... + 3 + 2 + 1
2S = (1 + 40) + (2 + 39) + ... + (39 + 2) + (40 + 1) = 40×41
S = 20×21 = 420
Then the sum you want is 2×420 = 840.
