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Greeley [361]
3 years ago
12

Find the equation of a line that passes through the point (4,2) that is perpendicular to the line y = x. Show your work.

Mathematics
1 answer:
maria [59]3 years ago
5 0
If it has to be perpedicular to y = x, then the slope has to be -1/x because perpedicular slope is the opposite reciprocal. Now plug what you know into the point slope formula. 

y - 2 = -1/1 (x - 4)

***** Since -1/1 is the same as -1, it can be rewritten as -1. ****************

y - 2 = -1 (x - 4)

Now distribute -1 times x and -4.

y - 2 = -x + 4

Add 2 to both sides to get y by itself. 

y = -x + 2

Your answer should be:

y = -x + 2
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a) P(0, <u>2</u>), Q(<u>4</u>, 0)

b) Please find attached the plot of the points P and Q on a chart made with MS Excel

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Step-by-step explanation:

The given equation for the line is 4·x + 2·y = 8

a) The coordinates of P = P(0, _)

Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)

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y = (8 - 4·x)/2 = 4 - 2·x

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With the help of MS Excel, the points P and Q are plotted in the attached graph

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