Answer: d=12
Step-by-step explanation:
![\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5C%5C%5Cfrac%7B3d-2%7D%7B8%7D%20%3D-d%2B16%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%5Cfrac%7B3d-2%7D%7B8%7D%20%3D-d%2B%5Cfrac%7B16%2A4%2B1%7D%7B4%7D%20%5C%5C%5C%5C%5Cfrac%7B3d-2%7D%7B8%7D%20%3D-d%2B%5Cfrac%7B64%2B1%7D%7B4%7D%20%5C%5C%5C%5C%5Cfrac%7B3d-2%7D%7B8%7D%20%3D-d%2B%5Cfrac%7B65%7D%7B4%7D)
Multiply both parts of the equation by 8:
![\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\](https://tex.z-dn.net/?f=%5Cdisplaystyle%5C%5C3d-2%3D%28-d%2B%5Cfrac%7B65%7D%7B4%7D%20%29%288%29%5C%5C%5C%5C3d-2%3D-8d%2B65%2A2%5C%5C%5C%5C3d-2%3D-8d%2B130%5C%5C%5C%5C3d-2%2B2%3D-8d%2B130%2B2%5C%5C%5C%5C3d%3D-8d%2B132%5C%5C%5C%5C3d%2B8d%3D-8d%2B132%2B8d%5C%5C%5C%5C11d%3D132%5C%5C)
Divide both parts of the equation by 11:
![d=12](https://tex.z-dn.net/?f=d%3D12)
Answer:
idont knowwwwwwwwwwwwwwwwww
Step-by-step explanation:
9514 1404 393
Answer:
(-3, 3)
Step-by-step explanation:
The blanks are trying to lead you through the process of finding the point of interest.
__
The horizontal distance from T to S is <u> 9 </u>. (or -9, if you prefer)
The ratio you're trying to divide the line into is the ratio that goes in this blank:
Multiply the horizontal distance by <u> 2/3 </u>. (9×2/3 = 6)
Move <u> 6 </u> units <u> left </u> from point T.
The vertical distance from T to S is <u> 6 </u>.
Multiply the vertical distance by <u> 2/3 </u>. (6×2/3 = 4)
Move <u> 4 </u> units <u> up </u> from point T.
__
Point T is (3, -1) so 6 left and 4 up is (3, -1) +(-6, 4) = (3-6, -1+4) = (-3, 3). The point that is 2/3 of the way from T to S is (-3, 3).
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2![(x+1)^2](https://tex.z-dn.net/?f=%28x%2B1%29%5E2)
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Hello!
In our triangle, c is the hypotenuse. We are given an adjacent side length to our angle. This means we will use the cosine. Let's find it first.
cos54≈0.59
This gives us the equation below.
0.59=9/c
0.59c=9
c≈15.25
Therefore, c is equal to about 15.25
I hope this helps!