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hram777 [196]
4 years ago
11

Part A: Write an algebraic expression for 8 more than 5 times a number.

Mathematics
2 answers:
jok3333 [9.3K]4 years ago
4 0
Part A: 5x + 8
Part B: four times the sum of a number and six
meriva4 years ago
4 0
8 more than means plus 8
5 times a umber is 5n when the number is n
8 more than 5 times a number means 8+5n


B. 4 times the sum of a number and 6
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Find the value of w.<br> 1080<br> 400<br> w<br> z<br> w = [?]
Leto [7]

Answer:

w = 54°

Step-by-step explanation:

The inscribed angle w is half the measure of its intercepted arc, that is

w = \frac{1}{2} × 108° = 54°

8 0
3 years ago
Suppose you are representing the employees at a large corporation during contract negotiations. You have a list of the salaries
evablogger [386]

Answer:

Median

Step-by-step explanation:

Median is ascertained by arranging a set of data in either ascending or descending order and picking the number that appears In the middle. The measure of center to use for this test is the median because it will represent the employees, it helps to arrange their income accordingly and the central item is determined.

7 0
3 years ago
What's 92010÷7X01910​
Nostrana [21]

Answer:

6.8818249813

Step-by-step explanation:

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4 0
4 years ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
3 years ago
Expand:<br> 4(5x+5) - 3(2x + 4)
aliina [53]

Answer:

14x + 8

Explanation:

⇒ 4(5x+5) - 3(2x + 4)

distribute inside parenthesis

⇒ 4(5x) + 4(5) - 3(2x) - 3(4)

multiply the variables

⇒ 20x + 20 - 6x - 12

collect like terms

⇒ 20x - 6x + 20 - 12

subtract like term

⇒ 14x + 8

3 0
2 years ago
Read 2 more answers
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