(i) The simultaneous equations in a, b and c are a+b+c = 7 , 4a+2b+c = 9 & 9a+3b+c = 13
(ii) Expression for nth term = n²-n+7
The first three terms of the sequence are 7, 9, 13
nth term = an²+bn+c
If we put n = 1 then,
1st term = a(1)²+b+c
⇒ a+b+c = 7 ......(1)
If we put n = 2 then,
2nd term = a(2)²+b×2+c
⇒ 4a+2b+c = 9 ........(2)
3rd term = a(3)²+b×3+c
⇒ 9a+3b+c = 13 .......(3)
Multiplying 4 with (1) and subtract (2) from (1) we get,
(4a+4b+4c)-(4a+2b+c)=28-9
⇒ 4a+4b+4c-4a-2b-c=19
⇒ 2b+3c=19 .....(4)
Multiplying 9 with (1) and subtract (3) from (1) we get,
(9a+9b+9c)-(9a+3b+c)=63-13
⇒ 9a+9b+9c-9a-3b-c=50
⇒ 6b+8c=50
⇒ 3b+4c=25 .....(5)
Multiplying 3 with (4) and multiplying 2 with (5), then subtract (5) from (4),
3(2b+3c)-2(3b+4c)=57-50
⇒ 6b+9c-6b-8c=7
⇒ c = 7
From (5),
3b+28 = 25
⇒ 3b = -3
⇒ b = -1
From (1),
a+(-1)+7 = 7
⇒ a-1=0
⇒ a=1
So, nth term = n²-n+7
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The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane
Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
Answer:
Wilhelmina will put 1.66 ounces of peanut butter on each sandwich.
Step-by-step explanation:
Given:
Ounces of peanut butter Wilhelmina has = 
Number of sandwiches prepared by her = 
According to the question:
She puts equal amount of peanut butter on each sandwiches.
So,
We have to find the quantity of peanut butter used for each sandwiches.
Here the distribution is equal so we have to use division method.
Let ounces of peanut butter applied on each sandwich be 'x'
⇒ 
⇒ 
⇒
Ounces
So each sandwich will get 1.66 ounces of peanut butter.
Answer:
37
Step-by-step explanation:
f(x) = 2x-1
g(x) =x^2 +3
f°g(x) = means put g(x) in for x into the function f(x)
f(g(x)) = 2 (g(x)-1
=2(x^2 +3) -1
Distribute
= 2x^2 +6-1
=2x^2 +5
Now we let x=-4
f(g(-4)) = 2 (-4)^2 +5
=2(16) +5
=32+5
=37
Answer:
5
Step-by-step explanation:
WHen f(x) = f(5)
x=5
therefore y = 5
Hope that helped!!! k