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USPshnik [31]
3 years ago
15

36 is _______% less than 60?

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
6 0
<span>36 is _______% less than 60?

36=60x
(divide both sides by 60)

x=.6

.6 as a percent is 60

60 percent subtracted from 100 is 40

40 is your answer


hope this helps



</span>
Arte-miy333 [17]3 years ago
4 0
60*(1-x)=36
60-60x=36
-60x=36-60
-60x=-24
x=24/60
x=4/10
x=2/5
x=0.4

36 is 40% less than 60
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Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
The boys had 5 4 6 gallons of water to share throughout the day. James drank 1 1 3 5 6 1 2 gallons and Simon drank 2 3 gallon. H
dsp73

Answer:

1\frac{1}{3}

Step-by-step explanation:

Total Volume of Water = 5\frac{4}{6}

Volume drunk by James =1\frac{1}{3}

Volume drunk by Simon =\frac{2}{3}

Volume drunk by Matthew = 1\frac{1}{2}

Volume drunk by Gilbert =\frac{5}{6}

Total Volume Drunk (i.e. The Sum) = 1\frac{1}{3} + \frac{2}{3} + 1\frac{1}{2} +\frac{5}{6}=\frac{13}{3}

Volume of water Left = Total Volume of Water-Total Volume Drunk

= 5\frac{4}{6}-\frac{13}{3} =\frac{4}{3}=1\frac{1}{3}

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