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2 years ago

Can someone please help me

Mathematics

1 answer:

vivado [14]2 years ago

4 0

Add the 2 1/2 to the other side to get rid of to isolate the x
-27/4= 1/2x divide by 1/2
-27/2=x

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william is thinking of two numbers both numbers are square numbers greater than 1 the sum of numbers is 100 write down two numbe

zheka24 [161]

Answer:

Step-by-step explanation:

At first,

Let start writing the squares of number 0 to 10,

0²=0

1²=1

2²=4

3²=9

4²=16

5²=25

6²=36

7²=49

8²=64

9²=81

10²=100

Now,

According to your question,

The two numbers should be square numbers
They should be greater than 1.
Their sum should be 100.

Hence, your given conditions matches with the numbers 64 and 36.

Therefore, the numbers are 64 and 36.

64 and 36 are greater than 1.
64 is a square of 8 and 36 is the square of 6.
64+36=100

3 0

2 years ago

It takes 4 1/2 cups of cherries to make a cherry pie. Russell wants to make 4 cherry pies. How many cups of cherries will Russel

atroni [7]

Answer:

18 cups.

Step-by-step explanation:

Multiply 4.5 by 4.

3 0

2 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

2 years ago

The vertex form of an equation is y = 3(x + 2)2 + 1. What is the standard form of the

Zigmanuir [339]

Answer:

y=3x^2+12x+13

a=3

b=12

c=13

3 0

2 years ago

10 2⁄3 yards = how many feet

ollegr [7]

Answer:

10 2/3 yards = 32 feet

Step-by-step explanation:

there is 3 feet in one yard

4 0

2 years ago