if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
Answer:
<em>9 sheep and 5 goats</em>
Step-by-step explanation:
s + g = 14
125s + 75g = 1500
125( 14 - g ) + 75g = 1500
1750 - 125 g + 75g = 1500
50g = 250
g = <em>5 goats</em>
s = <em>9 sheep</em>
Answer:
A) 
B) - 5
C) Not Possible
D) 5
E) 
- Step-by-step explanation:
- All integers are rational numbers. But not all rational numbers are integers.
- All whole numbers are integers. But not all integers are whole numbers.
I am a rational number but not an integer. Located on the right of 0.
This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form
.
From, the options
would fit this description.
I am a rational number and an integer but not a whole number.
This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.
I am a whole number but not an integer.
This is clearly not possible because all whole numbers are a subset of integers.
I am a rational number, a whole number and an integer.
This means it is a positive integer. 5 would fit this description.
I am a rational number but not an integer; located on the left side of 0.
This means it is a negative number.
should be the answer.