Here, trapezoid is composed of two triangles, and one rectangle.
So, Area of rectangle = 4 * 7 = 28 cm²
Area of a triangle = 1/2 * 3 * 7 = 21/2 = 10.5 cm²
Area of Trapezoid = area of rectangle + 2(area of triangle)
= 28 + 2(10.5)
= 28 + 21 = 49
In short, Your Answer would be 49 cm²
Hope this helps!
C= 2 (pi) r
d= 14 cm
d= 2r
r= 7 cm
c= 2 (pi) (7cm)
c= 43.98
hope that helps
Answer:
since the lengths are consecutive odd numbers and the perimeter of the triangle is 51cms. Let x be the unknown length.
so 3x=51 ; x=17 . now the sides can be 15cms, 17cms, 19cms.
check Add them up it is 51cms which is the perimeter and the consecutive odd numbers
Answer:
-5
Step-by-step explanation:
h(x) = -3x - 2
h(x) = 1
[ just put '1' in place of every 'x' ]
-3(1) -2
= -3 -2
= -5 (answer)
A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
