Find two consecutive odd integers such that their product is 35 more than 8 times their sum
1 answer:
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Remember some simle log rules
loga+logb=log(ab)
xloga=loga^x
means 
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
loga+logb=log(ab)
xloga=loga^x
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
If tan(x) = a/4, then a is opposite <span>to the angle x and 4 </span><span>is adjacent to the angle x
</span>If cos(x) = 4/b, then 4 is adjacent to the angle x and b is the hypotenuse
sin(x) = opposite/hypotenuse = a/b
Answer is D.
</span>If cos(x) = 4/b, then 4 is adjacent to the angle x and b is the hypotenuse
sin(x) = opposite/hypotenuse = a/b
Answer is D.
this is the answer step by step hope it helps
