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Gwar [14]
3 years ago
15

SURFACE AREA!! can someone please help me get the answer on these two I’m stuck

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

96 i think :)

Step-by-step explanation:

15x4=60

6x6=36

60+36=96

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What are any 9 perfect squares to type in the boxes?
Paul [167]

Answer:

1

4

9

16

25

36

49

64

81

100

Step-by-step explanation:

1 = 1²

4 = 2 x 2 = 2²

9 = 3 x 3 = 3²

16 = 4 x 4 = 4²

25 = 5 x 5 = 5²

36 = 6 x 6 = 6²

49 = 7 x 7 = 7²

64 = 8 x 8 = 8²

81 = 9 x 9 = 9²

100 = 10 x 10 = 10²

4 0
3 years ago
Write an equation of a line whose graph is parallel to the graph of y=3x-10.
Rzqust [24]
Y=3x plus or minus any number that is not 10.

The slope of your function has to stay 3x to be parallel with the function given. Just change the y-intercept (also known as the B value) to a number other than -10.
7 0
4 years ago
Read 2 more answers
A line with slope 3 passes through the point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2?
lana [24]
Hello!

So to find the y-coordinate we need an equation for the line. The equation we can use is

y = mx + b

In this we already know m(the slope which is 3) and we can find b by plugging in the points that are given.

10 = 3(0) + b
10 = 0 + b
10 = b

So now that we've found b, we can use this in our equation

y = 4x + b

So now we can plug in the x-coordinate that we know (2) and find the y - coordinate.

y = 4(2) + 10
y = 8 + 10
y = 18

18 is your y-coordinate 
4 0
4 years ago
Use the point-slope form, y - y1 = m(x - x1), to find the linear equation of a line that passes through the points
Andreyy89
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4 0
3 years ago
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Calculate the average rate of change for the given function, from x = 2 to x = 7.
Marina86 [1]
\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\

\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&0\\2&15\\7&30
\end{array}
\qquad 
\begin{cases}
x_1=2\\
x_2=7
\end{cases}\implies \cfrac{f(7)-f(2)}{7-2}\implies \cfrac{30-15}{5}
\\\\\\
\cfrac{15}{5}\implies 3
5 0
3 years ago
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