X-intercepts are found by factoring. Use the quadratic formula on the first since it's in standard form and you find that your x values are in fact -3 and 7. For the second one, use the Zero Product Property that says that x - 3 = 0 or x + 7 = 0. Therefore, x = 3 and -7. Signs are wrong. So not the second one. As for the third one, if you factor out a 3, your polynomial is exactly the same as the first one which did give us the desired x values. So the third one checks out. If you FOIL out the first one and then apply the quadratic formula you do get x = 3 and -7. So the fourth one checks out too. For the last one, putting it into the quadratic formula gives you x values of 3 and -7, so no to that one. Summary: 1st, 3rd, 4th have zeros of -3 and 7; 2nd and 5th do not.
Answer:
<em>y = (-4/3)*x + 7</em>
<em />
Step-by-step explanation:
The point-slope form of the equation of a line is: <em>y = a*x + b </em>
In the above equation, <em>a </em>is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]
The given line has a slope of -4/3, so that <em>a = -4/3 </em>
=> The equation of this line has a form as following: <em>y = (-4/3)*x + b (1)</em>
<em />
As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:
<em>y = (-4/3)*x + b</em>
<em>=> -5 = (-4/3)*9 + b </em>
<em>=> -5 = -12 + b </em>
<em>=> b = 7</em>
<em />
So that the equation in point-slope form of the given line is:
<em>y = (-4/3)*x + 7</em>
<em />
Answer:
(6,0) I think
my memory is rusty on this subject sorry if it's wrong.
Answer:
the M is (2,5)
Step-by-step explanation:
