Ok so first we need to distribute so:
<span>=<span><span><span><span><span>(4)</span><span>(b)</span></span>+<span><span>(4)</span><span>(2)</span></span></span>+</span>−<span>3b
</span></span></span>=<span>4b+8+−3b
</span>So now that we've distrubuted that we are now going to Combine Like Terms:
<span>=<span><span><span>4b</span>+8</span>+<span>−<span>3b
</span></span></span></span><span>=<span><span>(<span><span>4b</span>+<span>−<span>3b</span></span></span>)</span>+<span>(8)
Finally your answer is:
</span></span></span><span>=<span>b+<span>8
I hope this helps you!</span></span></span>
Answer:
Step-by-step explanation:5 pounds
35/13.3=2.63. 1.9x2.63=5kg
Answer:
a=8
Step-by-step explanation:
Part 1
<h3>Answer: 13</h3>
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Explanation:
We'll replace every copy of x with -3. Then use PEMDAS to simplify.
f(x) = -2x+7
f(-3) = -2(-3)+7
f(-3) = 6+7
f(-3) = 13
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Part 2
<h3>Answer: -11</h3>
---------------------
Explanation:
We work backwards in a sense compared to what part 1 did. Instead of finding f(x) based on x, we determine what x must be for a given f(x).
We'll replace f(x) with 29 and solve for x like so
f(x) = -2x+7
29 = -2x+7
-2x+7 = 29
-2x = 29-7
-2x = 22
x = 22/(-2)
x = -11
Note how if you replaced x with -11, we'd get,
f(x) = -2x+7
f(-11) = -2(-11)+7
f(-11) = 22+7
f(-11) = 29
which helps confirm we have the correct answer.
Consider right triangles BTZ and BUZ.
ZB = ZB (Common)
ZT = ZU (Given)
Therefore, ΔBTZ ≅ ΔBUZ (By RHS theorem)
Hence, by CPCTC,
∠BTZ = ∠BUZ