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zepelin [54]
3 years ago
10

A bullet of mass m1 = 0.020 kg is fired with initial speed v1 into a block of mass m2 = 0.500 kg that is initially at rest. The

bullet becomes embedded in the block and the pair slide along to the right a distance d= 0.35 m over a rough surface with uk = 0.25. the spring (with k = 450 N/m) is compressed by a distance of x = 0.075 m. work backwards and determine the initial velocity of the bullet.
Mathematics
1 answer:
kari74 [83]3 years ago
4 0
The answer wii ph hold be 147
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PLEASE HELP QUICKLY: GEOMETRY
WITCHER [35]

x/230=43/215

your answer would be 46

7 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP ASAP
Zielflug [23.3K]
They are alternate Exteror angles and internet but as for the question they would be corresponding angles
4 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
N76 [4]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

3 0
3 years ago
Sam created a porch that was part wooden and part concrete, as shown in the figure below. Note: Figure not drawn to scale If a =
rjkz [21]
Youre gonna have to upload a picture of the porch, "figure below"
3 0
3 years ago
Hey can you help me fast I am at a 83 and I need to get to a 90 on this.
jeyben [28]

Answer:

2/5

Step-by-step explanation:

First by looking, you have a slope going upward to the right so it is a positive slope.

Two points on the line that seem to go directly through the grid at the intersection points are ( -60, -90) and ( 40, -50).

Slope is Rise (y axis) over the Run (x axis).  The numbers above have x first and y second.

So the rise is the total distance between -90 and -50 which is 40.

The run is the total distance between 40 and -60 which is a total of 100.

It takes 40 units to get back to the 0 mark on the x axis and the another 60 units to get to the -60 point.

So you slop is 40/100.  You can simplify this down to 4/10 or even further to give you 2/5.

8 0
2 years ago
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