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2 years ago

Find the slope of the line that passes through (9,5) and (5, 4).

Mathematics

1 answer:

jarptica [38.1K]2 years ago

8 0

Answer:

Step-by-step explanation:

Rise over run

rise = 4 run=1

4/1=4

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Solve for Y -5y + 8 = -3y + 10?

lakkis [162]

Answer:

y=-1

Step-by-step explanation:

-5y+8=-3y+10

-5y-(-3y)+8=10

-5y+3y=10-8

-2y=2

y=2/-2

y=-1

7 0

2 years ago

What is 63 over 75 as a decimal?

marissa [1.9K]

Answer:

0.84

Step-by-step explanation:

Use a calculator. That would be 0.84.

3*21

Note that 63/75 = ---------- = 21/25. Multiplying top and bottom by 4 results

3/25 in 0.84 (so this answer checks out ok)

3 0

2 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

Simple interest

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

Interest compounded annually

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

2 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

2 years ago

Find the area of the parallelogram

iogann1982 [59]

Answer:

The answer is 32.

Step-by-step explanation:

Just multiply the height by the base length. 4*8=32

8 0

2 years ago