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iren2701 [21]
4 years ago
11

Help pleaseeeeeeeeeeeeeeeeee

Mathematics
1 answer:
sertanlavr [38]4 years ago
7 0
If you are in college, this question is likely done with calculus.
a = 12
k = 0.2
v(x) = 0 at the maximum after differentiation
V(x) = kx(a - x)

The easiest way to do this is to remove the brackets.
V(x) = akx - kx^2 Substitute the constants
V(x) = 12*0.2*x - 0.2x^2
V(x)/dx = 2.4 - 0.4x = 0 at the maximum
2.4 - 0.4x = 0
0.4x = 2.4
x = 2.4/0.4
x = 6
If you don't know any calculus yet, you can do this by completing the square.
  
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Answer: The length of the line B'C" is 1 unit.

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If A (2,2), B= (4,3) and C=(6,3).

Distance between (a,b) and (c,d): D=\sqrt{(d-b)^2+(c-b)^2}

Then, BC =\sqrt{(3-3)^2+(6-4)^2}

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3 years ago
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