Answer:
Part 1) ED=10 units
Part 2) DB=10 units
Part 3) EB= 20 units
Step-by-step explanation:
we know that
EB=ED+DB
ED=DB -----> given problem
Substitute the given values and solve for x
Find the value of ED
substitute the value of x
Find the value of DB
Remember that
ED=DB
therefore
Find the value of EB
EB=ED+DB
Answer:
1) 0.5 %
2) 16
Step-by-step explanation:
Since, a year = 12 months,
1 month =
year,
1) If the interest is compounded monthly,
Then, the rate per period = 
Given, annual rate = 6%,
So, the rate per period =
= 0.5%,
2) 1 year = 4 quarters,
If the loan is of 4 year and it is compounded quarterly,
Then, the number of compounding periods = number of years × 4
= 4 × 4
= 16
I would guess it is
200+9 +.50+.04
Answer:
i got 70
Step-by-step explanation:
Brain 4 Brain gets 42 more sweets Sara
Pip 5 How many sweets does Pip get?
Sara 1
when b = s + 42 find p b = 4s p = 5s
4s = s + 42 b/4 = s p = 5b/4
3s = 42
s = 14 b = 56 p = 70
I initially found the answer by trail and error, then I could figure out the equation.
s b p
1 4 5
10 40 50
16 64 90
14 56 70
Answer:
option 1) 50
Step-by-step explanation:
Let m and w denote the men and women respectively.
From the question, if the groom invited w number of women, then bride invited 2w number of women.
Also, if the bride invited m number of men,then the groom invited 2m.
Hence we can write the following maths equation:
w+2m=105.........1
2w+m=135.........2
We multiply eqn(1) by 2 to get eqn(3)
This implies that,
2w+4m=210.......3
We then subtract eqn (2) from eqn(3) to obtain;
3m=75
we divide through by 3


Substituting the value of m into eqn (1)
to find the value for w

subtracting 50 from both sides.



So we can say the :
bride invited 25 men and 110 women,
groom invited 50 men and 55 women.