Treat ast fraction
96/132
divide by 2,3,5,7 or factors starting from 2
96/2=48
132/2=66
48/66
divide 2
48/2=24
66/2=33
24/33
divide 3 since cannot divide 33 by 2
24/3=8
33/3=11
8/11
8:11
answer is 8:11
She would put 0.35 lbs of rice in each bag. Hope it helps!
Answer:
Step-by-step explanation:
Pay attention to the procedure:
(5(10)^2)^3/(10(5))^4. What we need is plug in the corresponding x and y values Then you have to do x squared before you multiply it by 5 like this: (5(100))^3/(10(5))^4 Now solve for what is in the top parenthesis. (500)^3/(10(5))^4 500^3=125000000 Now work on the denominator. Do what is inside the parenthesis first 10*5=50 Now (50)^4=6250000 Now divide the numerator and the denominator. 125000000/6250000 Which equals 20, Please check if I'm wrong but I think this is what you need
Area of the base = pi*(4x+2)^2 = pi*(16x^2 +16x +4)
volume of cylinder = pi*r^2 *h
V = pi *(16x^2 +16x +4)(5x+4) = pi*(80x^3 +80x^2 +20x +64x^2 +64x +16) =
= pi*(80x^3 +144x^2 +84x +16)
than we consider it without pi so result choice A. is right sure
hope helped
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.