1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LenKa [72]
3 years ago
9

Explain how a dense substance, such as metal, is able to float on a less dense substance, like water. Please Help! Remember you

will get rewards!!!
Physics
1 answer:
wlad13 [49]3 years ago
4 0
Archimedes and the principle of flotation ... "Cast iron sinks" ... unless it's a ship, of course is an old joke.
What has to happen is that supposing the object has a mass of 1kg, then it has to displace 1kg of water to float. However the volume of the object is decided by the object's density. Unless, that is, it is "hollowed out" or otherwise manipulated, such as is done in the hull of a metal ship ...
There's a thing called a "Eureka can" used in physics labs.

You might be interested in
Which happens to the magnetic field of a wire when you change the direction of the current in the wire? The magnetic field _____
Sophie [7]
B, also changes direction.
7 0
4 years ago
Read 2 more answers
A car moves 4m in 2s. The speed is_____.<br><br>(t/d)​
wariber [46]

Answer:

2m/s.

Explanation:

Speed = Distance / Time

= 4m / 2s

= 2m/s.

6 0
3 years ago
Read 2 more answers
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
bixtya [17]

Answer:

a. P=18.61\ W

b. \eta_c=0.6976=69.76\%

c. \eta=0.4718=47.18\%

Explanation:

Given:

  • temperature of the hotter reservoir, T_H=1250\ K
  • temperature of the colder reservoir, T_C=378\ K
  • heat absorbed by the engine, Q_H=1.42\times 10^{5}\ J
  • heat rejected to the cold reservoir, Q_L=7.5\times 10^4\ J
  • time duration of the energy transfer, t=1\ hr=3600\ s

<u>Now the work done by the engine:</u>

Using energy conservation,

W=Q_H-Q_L

W=14.2\times 10^4-7.5\times 10^4

W=6.7\times 10^4\ J

a.

<u>Hence the power output:</u>

P=\frac{W}{t}

P=\frac{6.7\times 10^4}{3600}

P=18.61\ W

b.

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{378}{1250}

\eta_c=0.6976=69.76\%

c.

now actual efficiency:

\eta=\frac{W}{Q_H}

\eta=\frac{6.7\times 10^4}{1.42\times 10^{5}}

\eta=0.4718=47.18\%

6 0
4 years ago
An incompressible fluid flows steadily through two pipes of diameter 0.15 m and 0.2 m which combine to discharge in a pipe of 0.
QveST [7]

Answer:

Average velocity = 1.835 m/s

Explanation:

Detailed explanation and calculation is shown in the image below

3 0
3 years ago
What force is necessary to accelerate a 70- kg object at a rate of 4.2 m/ s
ch4aika [34]
249 newtons hope it helps

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the capacity limitation of short-term memory?
    14·1 answer
  • A hollow metal cylinder has inner radius a, outer radius b, length L, and conductivity σ. The current I is radially outward from
    6·1 answer
  • A horse canters away from its trainer in a straight line, moving 120 m away in 15.0 s. It then turns abruptly and gallops halfwa
    12·1 answer
  • Why is it important to wear loose-fitting clothing when exercising?
    7·1 answer
  • A satellite orbits Earth. The only force on the satellite is the gravitational force exerted by Earth. How does the satellite’s
    6·2 answers
  • Please help me I will mark you brainlist
    12·1 answer
  • Which is a process that involves collecting information and ideas that are supported by belief or opinion?
    6·1 answer
  • Carbon (C) is an element found in living organisms. How would carbon be classified in the hierarchy of organisms?
    10·1 answer
  • Convert the following in to SI units without changing its values
    14·2 answers
  • The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!