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melisa1 [442]
3 years ago
7

A car moves 4m in 2s. The speed is_____.(t/d)​

Physics
2 answers:
wariber [46]3 years ago
6 0

Answer:

2m/s.

Explanation:

Speed = Distance / Time

= 4m / 2s

= 2m/s.

melamori03 [73]3 years ago
6 0
The answer is 2m/sec
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State 8/15 as a decimal correct to four decimal places​
gladu [14]

Answer:

8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus

0.5333

Explanation:

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3 years ago
What would be the effect of adding a proton to a nucleus?
Lisa [10]

Answer:

A

Explanation:

The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.

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2 years ago
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t
storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

T=2\pi\sqrt{\frac{I}{K}}

I=mR^{2}

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}

As dimensions of new balance wheel are one-third of their original values

R_{new}=\frac{R}{3}

\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega

5 0
3 years ago
Marisol breaks her leg when falling out of a tree.Why did her leg break?
sweet-ann [11.9K]
Because she fell out of a tree
3 0
3 years ago
Read 2 more answers
A girl takes her dog for a walk on a sunny beach. Find the force of gravity between the 45-kg girl and her 11-kg dog when they a
Lady_Fox [76]

The gravitational force acting between them is 8.25*10^-^9N

Data given;

  • M1 = 45kg
  • M2 = 11kg
  • r = 2.0m
  • G = 6.67*10^-^1^1m^3kg^-^1s^-^1

To solve this question, we need to apply gravitational force or energy formula.

<h3>Gravitational Force</h3>

This states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.

Mathematically;

F = \frac{GM_1M_2}{r^2} \\

let's substitute the values and solve

F = \frac{Gm_1m_2}{r^2}\\F = \frac{6.67*10^-^1^1 * 45 * 11}{2^2}\\F = 8.25*10^-^9N

The force of gravity acting between them is 8.25*10^-^9N

Learn more on gravitational force here;

brainly.com/question/11359658

4 0
3 years ago
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