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3 years ago

Solve for x. x+4/x+9= 6/5 / is a division bar.

1 answer:

7 0

Times both sides by (x+9). You would get x+4 = (x+9)(6)/5. Then times by 5, when everything is expanded you should get 5x + 20= 6x + 54. All you have to do now is collect like terms and solve for x. You should get x = -34

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Please help. If U = 5 feet, V = 8 feet, W = 3 feet, X = 6 feet, Y = 13 feet, and Z = 4 feet, what is the area of the object?

Natalija [7]

Answer:3

Step-by-step explanation:

Because it’s the right equation

4 0

4 years ago

3x^2+5x_=2+_

tatiyna

IT DOES NOT MATTER YOU WILL NOT BE ABLE TO SOLVE THIS QUESTION
YOU WOULD GET 5x = 2 + 3x^2 AND YOU WOULD STILL NOT BE ABLE TO SOLVE YOU COULD GET 3x^2 = 2 + 5x AND YOU COULD NOT SOLVE.
THE REASON WHY IS BECAUSE YOU HAVE TO HAVE THE SAME X TO ADD THEM OR MINUS THEM< WHICH IN THIS CASE ONE IS REGULAR BUT THE OTHER IS SQUARED. AND ALSO THE TWO NEEDS SOMEONE TO GO WITH< BUT THE IS ONLY ONE OF HIS TYPE SO HE CAN'T.
WELCOME :/

3 0

3 years ago

If ON=8x*8, LM=7x+4, NM=x-5, and OL=3y-6, find the values of x and y for which LMNO must be a parallelogram. The diagram is not

lana66690 [7]

ON = 8x • 8
LM = 7x + 4
NM = x - 5
OL = 3y - 6

OL is congruent & parallel to NM
LM is congruent & parallel to ON

So,
$8x \times 8 = 7x + 4$
Simplify
$64x = 7x + 4$
subtract 7x from both sides
$57x = 4$
divide 57 from both sides
$x = \frac{4}{57}$
Substitute x into equations
$8x \times 8 = 7x + 4 = 4 \frac{28}{57}$

$3y - 6 = x - 5$
$3y - 6 = 4 \frac{28}{57} - 5$
$3y - 6 = - \frac{28}{57}$
NM & OL = -28/57
ON & LM = 4 + (28/57)

4 0

3 years ago

Read 2 more answers

Marrisa added 1.56 and 13.47. She got 29.07. What mistake could Marrisa have made? She forgot to move the decimal point to the l

Keith_Richards [23]

Answer: She lined up the front numbers instead of the decimal places.

Step-by-step explanation:

A correct addition or subtraction in decimals should be lining up decimal places in order to make sure that you are adding or subtracting in the same place.

1.56 + 13.47=15.03

Hope this helps!! :)

8 0

3 years ago

Read 2 more answers

Abigail is raising money for a school trip by selling bags of chips and packs of cookies. The price of each bag of chips is $1.5

Mkey [24]

The number of bags of chips sold is 8 and the number of packs of cookies sold is 12

<em><u>Solution:</u></em>

Let "a" be the number of bags of chips sold

Let "b" be the number of packs of cookies sold

Given that,

Cost of one bag of chips = $ 1.50

Cost of one pack of cookies = $ 1.25

Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies

<em><u>So we can frame a equation as:</u></em>

Number of bags of chips sold + number of packs of cookies sold = 20

a + b = 20 ---- eqn 1

Also given that Abigail made $27 from selling

number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27

$a \times 1.50 + b \times 1.25 = 27$

1.5a + 1.25b = 27 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

From eqn 1,

a = 20 - b ---- eqn 3

Substitute eqn 3 in eqn 2

1.5(20 - b) + 1.25b = 27

30 - 1.5b + 1.25b = 27

-0.25b = -3

Therefore from eqn 3,

a = 20 - b = 20 - 12 = 8

number of bags of chips sold = 8

number of packs of cookies sold = 12

3 0

3 years ago