1/11
143 divided by 13 is 11.
That is 2 of the y^2
that means 2y^2 aka 2 times y^2
Answer:
a. AB = 6
b. m<F = 70°
Step-by-step explanation:
a. Triangle ABC is an equilateral triangle because all three angles are equal to 60° each. Therefore, all three sides would also be equal to each other.
Thus, since one of the sides, BC = 6, therefore:
AB = BC = 6
b. The markings indicate that two sides of ∆EDF (ED & EF) are equal in length. This means that ∆EDF is an isosceles having two equal base angles (<F and <D).
This:
m<F = (180 - m<E)/2
m<F = (180 - 40)/2
m<F = (140)/2
m<F = 70°
Here the order matters (the medal of the 1st is different from the medal of the 2nd, etc.)
So it's a permutation (arrangement) of 6 chosen among 31:
³²P₆ = (n!)/(n-r)! = 32!/26! = 652,458,240
Another method:
the 1st medal could be won by 32
the 2nd medal could be won by 31 .
the 3dd medal could be won by 30
.etc. etc.
the 6th medal could be won by 27
.
Then the number of possibilities = 32x31x30x29x28x27 =652,458,240
