Answer:
(B) Segments MA and MB
Step-by-step explanation:
The tangent to the circle at a point is perpendicular to the radius of the circle drawn to the point of tangency.
Tangent at a point is unique.
Since there can be no two tangents at a point on circle, the options (b) and (c) are ruled out.
Now, if OA is perpendicular to MA, MA is the tangent else if OA is perpendicular to PA, PA is the tangent. Same is the case with point B.
Tangents from the same external point has same length.
MA = MB since they are the radii of the same circle with center M.
Hence, MA and MB meet all the requirements of the tangents.
Answer:
-x² + 12x + 3
Step-by-step explanation:
Step 1: Write expression
5x² + 9x + 3 - (6x² - 3x)
Step 2: Distribute
5x² + 9x + 3 - 6x² + 3x
Step 3: Combine like terms
-x² + 12x + 3
Answer:
all correct
Step-by-step explanation:
<span> x=<span><span><span><span>3</span> and </span></span>y</span></span>=<span>2 to check use the first equation y=5x-13 you plug in x which is 3 5 times 3 equals 15 15-13 equals 2 y=2</span>