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A pastry chef wants to bake and sells fries. Before they start production, they need to make sure they can make a profit with th
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The maximum value of the objective function is 330
<h3>How to maximize the objective function?</h3>The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
#SPJ1
Answer:
2½ h
Step-by-step explanation:
Assume the graph is like the one below.
The graph shows how Erin's distance varies with time.
To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.
From there, draw a horizontal line until it hits the graph.
Then drop a vertical line to the horizontal axis.
It hits half-way between 2 and 3.
It takes Erin 2½ h to run 25 mi.
