Answer:
4
Step-by-step explanation:
Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
840 is the answer
i hope i helped!
Answer:
Step-by-step explanation:
let the first angle be 5x
second be 4x
and third be 1x
as we know that by adding all the sides of triangle we get 180°
therefore ,
5x+4x+1x=180°
10x=180°
hence ,
x=18°
first angle - 18*5 = 90°
second angle - 18*4=72°
third angle - 18°
HOPE THIS HELPS YOU !!!
Answer:
D.) Add 16 to both sides of the equation
Step-by-step explanation:
By adding 16 to both sides, you are eliminating the -16 on the left. You must do it to both sides in order to balance the equation.
