Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
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Answer:
{5, 10, 15, 20}
Step-by-step explanation:
Multiples of 5 are of the form 5n, where n is an integer. The ones of interest will satisfy ...
0 < 5n < 23
0 < n < 4.6
That is, the multiples of 5 we want are for values of n that are 1 through 4. The set is ...
5 × {1, 2, 3, 4} = {5, 10, 15, 20}
Answer:
dy/dx= cos(ln(x))/x
Step-by-step explanation:
y=sin(ln(x)) given
We have to use chain rule to differentiate!
Let u=ln(x) then du/dx=1/x
So we have
if y=sin(ln(x)) then y=sin(u) and dy/dx=dy/du * du/dx=cos(u) *1/x
where again u=ln(x) so
dy/dx=cos(ln(x)) *1/x
dy/dx=cos(ln(x))/x
I hope I have the right intepretation because I do see a ? in between sin and (ln(x)) .
