This problem can be represented through the following equation
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Using a system of equations, it is found that initially Ada has $0.385.
For the system, we have that the variables are:
- x is Ada's amount.
- y is Betty's amount.
- z is Chris's amount.
- w is David's amount.
$45 total, hence:
Ada <u>gets 2 from Betty</u>, hence:
<u>Chris triples</u> his money and <u>David's</u> money is <u>cut by half</u> four of them have the same amount, hence:
Then:
Solving for w, we find Ada's initial amount.
Initially, Ada has $0.385.
A similar problem is given at brainly.com/question/6120515
Answer:
Step-by-step explanation:
f(x) = x + 1, find f(x+3)
f(x+3) = x + 3 + 1 = x + 4
-24 <span>≤ x- 3 -8x
+3 +3
-21 </span><span>≤ x - 8x
-21 </span><span>≤ -7x
/-7 /-7
x </span><span>≤ 3</span>
The work is done on the toy car is 164.4 J .
<h3>How to calculate work done?</h3>
We are aware that the definition of work is the multiplication of the magnitude of the displacement (d) and the component of the force acting in the displacement direction.
When an object moves over a distance while being applied with force, the work is considered to have been completed.
Three categories can be used to classify the type of labor performed. Positive work, negative work, and zero work are the three types. The angle between force and displacement determines the kind of work that is done. Positive work is defined as any work that causes an object to move in the direction of the applied force.
Given ,
Work = force * distance
Force = 5.2 N
Distance = 32 m
So ,
Work = 5.2 * 32
= 166. 4 J
Therefore the work is done is 164.4 J
To learn more about work done refer to:
brainly.com/question/25816840
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