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Advocard [28]
3 years ago
12

In pauls bicycle shop, 40 bicycles are inspected. If 20 needed new tires and 30 needed gear reports, answer the following: a) wh

at is the greatest number of bikes that could have needed both. B) least number that could have needed both . C) what is the greatest number of bikes that could have needed neither.
Mathematics
1 answer:
Arisa [49]3 years ago
7 0
<span>There are three possibilities. 1. Of the 30 bikes that needed gear repairs, 20 also needed tires. 2. Of the 30 bikes that needed gear repairs, 10 also needed tires. 3. Of the 30 bikes that needed gear repairs, between 10 and 20 also needed tires.</span>
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How do you do this question?
e-lub [12.9K]

Answer:

D. dA/dt = 4h dh/dt in²/sec

Step-by-step explanation:

Given:

A = wh

w = 2h

Substitute:

A = 2h²

Take derivative with respect to time:

dA/dt = 4h dh/dt

dA/dt has units of in²/sec.

7 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
AfilCa [17]

Answer:

36.1 in.

Step-by-step explanation:

1:19 , 1.9in.

1.9 * 19

which equals 36.1 in.

(HOpe This hElps:)

If correct plz give brainliest ; )

8 0
2 years ago
Read 2 more answers
X - 4 &lt;-4+ what’s the answer?
LekaFEV [45]

Answer:

Step-by-step explanation:

the answer is x<0

because

x-4+4<-4+4

6 0
3 years ago
What is the solution to the system of equations? Use the substitution method.
ludmilkaskok [199]
The answer is A. (3,-1/2)
3 0
2 years ago
does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
3 years ago
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