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Advocard [28]
3 years ago
12

In pauls bicycle shop, 40 bicycles are inspected. If 20 needed new tires and 30 needed gear reports, answer the following: a) wh

at is the greatest number of bikes that could have needed both. B) least number that could have needed both . C) what is the greatest number of bikes that could have needed neither.
Mathematics
1 answer:
Arisa [49]3 years ago
7 0
<span>There are three possibilities. 1. Of the 30 bikes that needed gear repairs, 20 also needed tires. 2. Of the 30 bikes that needed gear repairs, 10 also needed tires. 3. Of the 30 bikes that needed gear repairs, between 10 and 20 also needed tires.</span>
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Subtract 10 from both sides.

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Ilia_Sergeevich [38]

Answer:

x = \frac{57}{29} \ , \ y = \frac{12}{29}

Step-by-step explanation:

                            2x + 5y = 6     --------( 1 )

                            5x - 2y = 9     --------( 2 )

                        _____________

     ( 1 ) x 5 =>     10x + 25y = 30   -----------( 3 )

     ( 2 ) x 2 =>    10x - 4y = 18       ----------- ( 4 )

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    ( 3 ) - ( 4 ) =>    0 +  29y = 12

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Substitute y in ( 1 ) =>

                            2x + (5 \times \frac{12}{29}) = 6\\\\2x + \frac{60}{29} = 6\\\\2x = 6 - \frac{60}{29}\\\\2x = \frac{174 - 60}{29}\\\\x = \frac{114}{29 \times 2}\\\\x = \frac{57}{29}

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Answer:

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Step-by-step explanation:

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