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3 years ago

Please help me with this question

Mathematics

1 answer:

Musya8 [376]3 years ago

8 0

I’m not sure, maybe try going on quizzes

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Milton makes trail mix for his hiking group he makes a 1 and 1/4 pound of peanuts 14 oz of raisins 12 oz of walnuts in 10 oz of

strojnjashka [21]

Answer:

Each hiker receives 7 ounces of trail mix

Step-by-step explanation:

Trail mix=quantity of peanuts+quantity of raisins+quantity of walnuts+quantity of chocolate chips

where;

Quantity of peanuts=1.25 pounds

Quantity of raisins=14 oz, since 1 pound=16 oz.

Quantity of raisins=(14/16)=0.875 pounds

Quantity of walnuts=12 oz=(12/16)=0.75 pounds

Quantity of chocolate chips=10 oz=(10/16)=0.625 pounds

Replacing;

Trail mix=(1.25+0.875+0.75+0.625)=3.5 pounds

Trail mix=Quantity per hiker×Number of hikers

where;

Trail mix=3.5 pounds

Quantity per hiker=q

Number of hikers=8

Replacing;

3.5=q×8

q=3.5/8=0.4375 pounds

I pound=16 ounces

q=0.4375×16=7 ounces

Each hiker receives 7 ounces of trail mix

8 0

2 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

Can someone please help me.

Art [367]

I will give you everything I can do:

11)

Lets say Car A travels at x mph. That means Car B travels at x+2 mph.

Both of them are traveling towards each others, so we can say the total speed is 2x+2.

Now i takes 3 hrs and we know the distance.

Since R*T=D

Then 3(2x+2)=270

So 2x+2=90

2x=88

x=44

12)

To find perpendicular we want to find the opposite reciprocal of the original slope. Therefore the slope is 3/2.

Now we must find the equation of the line with the given variable.

First find b.

5=3/2*4+b

b = -1

So the equation of this line is:

y=3/2x-1

13) All work will be shown below.

6-3(-2-4x)=2(3(x-4)+7)

6+6+12x=2(3x-12+7)

12+12x=2(3x-5)

12+12x=6x-10

6x=-2

x = -1/3

14)

First we must find the amount each train traveled.

The speed of F train(Freight train)=x

The speed of P train(passenger train)=x+6

Their combined speed is 2x+6

It takes 2 hrs to cover 100 miles

So 2(2x+6)=100

2x+6=50

2x=44

x=22

So the freight train covered 44 miles and the passenger train covered 56 miles.

To find average speed you must do Total Distance/Total Time.

44/2 and 56/2

Which are 22 and 28.

The average speed of F train is 22 mph and average speed of P train is 28 mph.

15) Again opposite reciprocal.

3/5 -> -5/3

Work:

-4=-3*-5/3+b

-4=5+b

b=-9

y = -5/3x-9

16)

F=kx-kx0

First kx0 = 0

So F=kx

So x=F/k

4 0

2 years ago

Helpppppp helpppppppp plssssssssss

Vinil7 [7]

Answer:

Scales-No equal sides

Isosceles- 2 Equal

Equilateral-

Right-90 degree

Obtuse- Obtuse Angle

8 0

3 years ago

Solve the inequality.<br>–5r+3≥-2

andrew-mc [135]

Answer:

the answer is r<1 that's the inequality

5 0

3 years ago