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ANEK [815]
2 years ago
13

Match the missing term with the perfect square trinomial 9X^2+?+25 49 6x 36 30x

Mathematics
1 answer:
Igoryamba2 years ago
4 0
9x^2+t+25=(ax+b)^2

9x^2+t+25=a^2*x^2+2abx+b^2 so

a^2=9 so a=3

b^2=25 so b=5 then

t=2ab using a and b from above

t=2*3*5=30

So the missing term is 30x
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7>-4; subtract 7 from both sides
motikmotik

Answer:

The end result would be 0>-11

Step-by-step explanation:

Subtract 7 from each number and then just write it again.

7 - 7 = 0

-4 - 7 = -11

0>-11

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3 years ago
Someone please tell me how to work out this type of problem i completely forgot
fenix001 [56]

Answer:

Plug the x-values into the equation to get the y values. This will give you coordinates that you can graph a line with.

Step-by-step explanation:

For x = -5:  y = -3 - 2 * (-5) = 7, so the coordinates are (-5, 7)

For x = -2:  y = -3 - 2 * (-2) = 1, so the coordinates are (-2, 1)

(Etc.)

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Equivalent fractions for 9/11, 15/17, and 2/3 using the least common denominator.
TiliK225 [7]
The (small) challenge here is to determine what the LCD is.  Since 11, 17 and 3 are all prime, we find the LCD by multiplying them together:  561.

Then 9/11= 459/561; 15/17 = 495/561; and 2/3 = 375/561.
8 0
3 years ago
The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th
makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 e^{kt}

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070  e^{3k}

\frac{9000}{4070} = e^{3k}

\frac{900}{407}=e^{3k}

<u><em>Taking natural logarithm on both sides, we get:</em></u>

ln\frac{900}{407}=ln(e^{3k})

ln\frac{900}{407}= 3k ln<em>e</em>

ln<em>e</em>=1

ln \frac{900}{407}= 3k

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k =\frac{1}{3}(0.7936)

<em>k = 0.2645</em>

<em />

7 0
3 years ago
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