If the angles of a convex octagon are
then the smallest angle is 21°.
Given The exterior angles of convex octagon are 
and we have to find the value of smallest angle.
The sum of the angles of a convex octagon is 360°
so to calculate the smallest angle we need to find out the value of x first and which is calculated by summing up all the exterior angles and put them equal to 360.
(2x+6)+(x+13)+(2x-1)+(2x+12)+(2x-17)+(3x-4)+(3x-10)+4x=360
2x+6+x+13+2x-1+2x+12+2x-17+3x-4+3x-10+4x=360
2x+x+2x+2x+2x+3x+3x+4x+6+13-1+12-17-4-10=360
19x-1=360
19x=360+1
19x=361
x=361/19
x=19
Putting the value of x in all the angles and we will find the following:
2x+6=2*19+6=44
x+13=19+13=32
2x-1=2*19-1=37
2x+12=2*19+12=50
2x-17=2*19-17=21
3x-4=3*19-4=51
3x-10=3*19-10=47
4x=4*19=76
Hence among all the exterior angles the smallest angle is 21°.
Learn more about angles at brainly.com/question/25716982
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Number 1- true
number 2- true
number 3- false
number 4- true
number 5- false
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Answer:
26
Step-by-step explanation:
We have to prove that Quadrilateral ABCD is a parallelogram.
The third step is m AEB = mCED
As ABCD is a quadrilateral, the point of intersection of diagonals being E.
In the first step while proving it is written that Diagonals bisect each other i.e
AE = EC and BE= ED
After drawing the quadrilateral it is being found that ∠AEB and ∠CED are vertically opposite angles.
Out of the given five options option (D) is the correct option. which is vertical angles theorem.
vertical angle theorem states that if two lines intersect at a point ,then their vertically opposite angles are equal.