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Salsk061 [2.6K]
3 years ago
6

Use spherical coordinates. evaluate (x2 + y2) dv e , where e lies between the spheres x2 + y2 + z2 = 1 and x2 + y2 + z2 = 25.

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0
\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

x^2+y^2=\rho^2\cos^2\theta\sin^2\varphi+\rho^2\sin^2\theta\sin^2\varphi=\rho^2\sin^2\varphi

\displaystyle\iiint_E(x^2+y^2)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=1}^{\rho=5}\rho^4\sin^3\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi
=\displaystyle2\pi\left(\int_{\varphi=0}^{\varphi=\pi}\sin^3\varphi\,\mathrm d\varphi\right)\left(\int_{\rho=1}^{\rho=5}\rho^4\,\mathrm d\rho\right)
=\dfrac{24992\pi}{15}
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<em><u /></em>x = \frac{-b+- \sqrt{b^2 - 4ac} }{2a}

<em><u>The setup is:</u></em>

<em><u /></em>ax^2+bx+c=0

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<em><u>Plug in the numbers according to the letter associated:</u></em>

<em><u /></em>x = \frac{8+-\sqrt{-8^2-4(4)(-60)} }{2(4)}

x = \frac{8+-\sqrt{1024} }{8}

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<em><u>Solve for addition and subtraction:</u></em>

<em><u /></em>x = \frac{8+32}{8}                                                                              x = \frac{8-32}{8}

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