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lana [24]
3 years ago
9

Need help please. ASAP!!

Biology
1 answer:
grandymaker [24]3 years ago
3 0
It would be the third and fifth one, from top to bottom.
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A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and t<span>he frequency of i allele is 0.5.
</span>
If:
I^{A} - <span>the frequency of IA allele
</span>I^{B} - <span>the frequency of IB allele
</span>i - t<span>he frequency of i allele

Then:
</span>I^{A} I^{A} + <span>I^{A} i - the frequency of individuals with A blood type
</span>I^{B} I^{B} + <span>I^{B} i - the frequency of individuals with B blood type
</span>ii <span>- the frequency of individuals with O blood type
</span>
Let's first take a look on the Dunker population:
I^{A} = 0.3
ii=0.16&#10;

<span>Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
</span>i= \sqrt{ii}
⇒ i =  \sqrt{0.16}
⇒ i=0.4

Now, we have the frequencies of two alleles (I^{A} and i). To calculate the frequency of I^{B}<span> allele, we will use the formula:
</span>I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.3-0.4
⇒ I^{B} = 0.3

Now, in the general population:
I^{A} = 0.4
ii=0.25

<span>Similarly to the work for the Dunker population:
</span>i= \sqrt{ii}
⇒ i = \sqrt{0.25}
⇒ i=0.5

I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.4-0.5
<span>⇒ I^{B} = 0.1
</span>


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