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3 years ago

Is 3z monomial,binomial or trinimail?

Mathematics

1 answer:

Ivan3 years ago

4 0

Answer:

monomial

Step-by-step explanation:

monomial, one term

binomial two terms

trinominal three terms

3z is one term so it is a monomial

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How to solve exterior angle for right triangle?

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3 years ago

You borrow $1900 to buy a refrigerator. The simple interest rate is 11%. You pay off the loan after 5 years. How much do you pay

leonid [27]

I = PRT is the formula to use for this.

I = (1900)(.11)(5)
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3 years ago

Is 2a * b = a^2 + b^2 true or false

alisha [4.7K]

First step of the equation is to simplify the equation 2a • b = a2 + b2 into 2 ab = a2 + b2. This cannot be factored anymore although. when we try to substitute a with 5 and b with 2, the answer in the right hand side of the equation is -9. hence the answer to this problem is false. we can try another values to verify.

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3 years ago

Which of the following best explains why tan5π/6 ≠ tan5π/3

Kobotan [32]

Answer:

The angles do not have the same reference angle.

Step-by-step explanation:

1) Angle 5π / 3 radians:

Convert radians to degrees: 5π/3 × 180° / π = 300°

300° is in the fourth quadrant

The reference angle for angles in the fourth quadrant is 360° - angle ⇒ 360° - 300° = 60°.

∴ The reference angle for this angle is 60°.

2) Angle 5π / 6 radians:

Convert radians to degrees: 5π/6 × 180° / π = 150°

150° is in the second quadrant

The reference angle for angles in the second quadrant is 180° - angle ⇒ 180° - 150° = 30°.

∴ The reference angle for this angle is 30°.

3) Conclusion:

Since the reference angles are different, the tangent ratios have different values.

tan (5π/3) = - tan(60°) = - √3

tan (5π/6) = - tan(30°) = - (√3)/3

Note that the tangent is negative in both second and fourth quadrants.

If correct please give brainliest

<em>Stay safe and healthy</em>

Thank You

3 0

3 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago