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alina1380 [7]
2 years ago
14

You bought a Nissan Xterra for $25,000. The car depreciates at a rate of

Mathematics
1 answer:
cestrela7 [59]2 years ago
4 0

Answer:

Why i dont know

Step-by-step explanation:

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In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?
Sphinxa [80]

Answer:

0.74

Step-by-step explanation:

72/97 is 0.74 rounded to the nearest hundredths.

6 0
3 years ago
(7-4n) x 6= I need the answer as quick as possible
Paraphin [41]

Answer:

42 - 24n

Step-by-step explanation:

(7-4n)  6

Distribute

7*6 - 4n*6

42 - 24n

4 0
3 years ago
Read 2 more answers
Write the equation 2x-3y=6in slope -intercept form​
Tcecarenko [31]

Answer:

y = 2/3 x -2

Step-by-step explanation:

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

We need to solve for y

2x-3y = 6

Subtract 2x from each side

2x-2x-3y=-2x+6

-3y = -2x+6

Divide  by -3

-3y/-3 = -2/-3x+6 /-3

y = 2/3 x -2

The slope is 2/3 and the y intercept is -2

7 0
2 years ago
If Erica has 7$ And her sister holly has some money too how much do they have in total
Dmitry [639]

Answer:

you cant figure that out.

Step-by-step explanation:

6 0
3 years ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
3 years ago
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