Given:
540 miles to college
average rate of 45 miles per hour
How many hours will it take him to get 3/4 of the way there?
540 miles * 3/4 = (540 * 3) / 4 = 1620/4 = 405 miles
405 miles / 45 mph = 9 hours.
It would take Tameron 9 hours to travel 3/4 of the way there.
Answer:
E) $1.05
Step-by-step explanation:
before sale: $1.35×12=$16.20
during sale: $0.95×(12×3)=$34.20
total money spent=$16.20+$34.20=$50.40
total bars bought=12+(12×3)=48
average=

Answer:
<u><em>Steven is 15 and one half years old now</em></u>
Step-by-step explanation:
<u />
Linear equations
Sometimes we need to know the value of a variable in a given equation and that variable is given as a polynomial of degree 1. Solving for that variable means isolating it and replacing the other known values
Steven was 7 years old eight and one-half years ago. If we call x as the actual age of Steven, his age eight and one-half years ago was

We know he was 7 years old then, so

We need to know his actual age, so let's solve for x, adding
to each side of the equation

Simplifying

Steven is 15 and one half years old now
Question: Is this some kind of mind trick riddle or what lol!
Answer:
x = 6 months.
The equation is given by $45 + ($49.45 × x) = ($56.95 × x).
Step-by-step explanation:
i) Let x be the number of months of Internet Service purchased till the Fast
Internet charges and Quick Internet charges become the same.
ii) Charges for Fast Internet for x months is given by $45 + ($49.45 × x)
iii) Charges for Quick Internet for x months is given by ($56.95 × x)
iv) According to the first statement we will now equate the equations in ii)
and iii) and solve for x.
Therefore, $45 + ($49.45 × x) = ($56.95 × x)
45 + 49.45 x = 56.95 x
Therefore (56.95 - 49.45) x = 45
7.50 × x = 45
Therefore x = 45 ÷ 7.5 = 6