Answer:
Assuming the length to be x and the width to be y.
Since the area is 64cm, hence
x*y = 64 (equation 1)
Since the perimeter is 40cm, hence
x + x + y + y = 40
2x + 2y = 40
2(x + y) = 2(20)
x + y = 20 (equation 2)
Hence by using simultaneous equation,
x = 20 - y (equation 3)
Substituting equation 3 into equation 1, we get
(20-y)*y=64
20y-y^2=64
Tidying up the equation,
y^2 - 20y + 64 = 0
By using factorisation,
(y-16)(y-4)=0
y=16 or y=4
By substituting y=16 into equation 1,
x*16=64
x = 4
By substituting y = 4 into equation 1,
x*4=64
x=16
Therefore,
The length is 4 cm while the width is 16 cm.
OR
The length is 16 cm while the width is 4cm.
Hope this helps!!
The legs are 5 inches long.
Use the Pythagorean theorem:
The length of the hypotenuse of the triangle is approximately 7 inches long.
Answer:
Step-by-step explanation:
hello :
the n-ieme term is : An=A1×r^(n-1)
A1 the first term r : the common ratio
in this exercice : A1 =15 r = 1/3 n = 4
A4=15×(1/3)^(4) =15×4^4 =3840
Answer:
The area of the triangle is of 21 units of area.
Step-by-step explanation:
The area of a triangle with three vertices 
is given by the determinant of the following matrix:
In this question:
Vertices (3,0) (9,0) (7,6). So
The area of the triangle is of 21 units of area.
