A simple random sample of 60 is drawn from a normally distributed population, and the mean is found to be 28, with a standard de
2 answers:
Answer:
The value of 27, because it’s greater than 26.7 and less than 29.3.
Step-by-step explanation:
You should find the confidence Interval at 95%
The formula to apply is;
C.I= x±z*δ/√n
where C.I is the confidence interval, x is the mean of the sample, z is the z* value from the standard normal distribution for 95% confidence interval, δ is the standard deviation and n is the sample size
Substitute values in the formula
Find δ/√n
Calculate z*δ/√n
C.I= 28±1.2652
Upper limit is = 28+1.2652=29.2625
Lower limit is =28-1.2652=26.7348
Solution
The value 27 is within 95% confidence interval because it is greater than 26.7 and less than 29.3
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Answer:
The last 2 statements are true
Step-by-step explanation:
given f(x) = x² + 6x and g(x) = 2x³
f(x) × g(x) = 2x³(x² + 6x) = 2 + 12
not 2 + 12x³
f(0) = 0 + 0 = 0 and g(2) = 2 × 2³ = 2 × 8 = 16
f(0 × g(0) = 0 × 16 = 0 ≠ 16
f(1) = 1 + 6 = 7 and g(1) = 2 × 1³ = 2
f(1) × g(1) = 7 × 2 = 14 ← True
g(x) × g(x) = 2x³ × 2x³ = 4 = 4
← True