6r - 3t = 6 /*8
6r + 8t = - 16 /*3
48r - 24t = 48
48r + 24t = - 48
---------------------- +
96r = 0
r = 0
t = ( -16 + 6r)/8 = - 16/8 = - 2
Answers:1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:1) Value of the functions as x increases.Function p:

As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1,
the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.While in the graph you see that the function
q has a horizontal asymptote that shows that the
limit of q (x) when x → ∞ is - 4.Then, the first answer is that
as x increases the value of p(x) approaches a number that is greater than q (x).2) y - intercepts.i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2ii) The y-intercept of q(x) is read in the
graph. It is - 3.
Then the answer is that
the y-intercept of the function p is greater than the y-intercept of the function q.
Given:
PV = 13,440
i = 5.86% , compounded monthly
t = 4 years
13,440(0.0586/12))/(1-(1+0.0586/12)^-48= 15,109.44
15,109.44 + 156.60 = 15,266.04
15,266.04 - 13,440.00 = 1,826.04
<span>1,826.04/15,266.04 = 11.96 % Percentage total of Finance Charge of the total loa</span>
Answer:
can u be more specific so i can properly help u
Explanation:
pls explain and i will edit my answer
Answer:
Step-by-step explanation:
<h3>Solution 1</h3>
The figure (kite) is symmetric and covers half of the area of rectangle with sides 8 units aby 10 units
<u>The area of the rectangle:</u>
<u>The area of the kite:</u>
- A = 1/2*80 = 40 sq. units
<h3>Solution 2</h3>
Split the kite into two triangles and calculate their area and add up
<u>Triangle DCB has b = 8, h = 2 and has area:</u>
- A = 1/2*8*2 = 8 sq. units
<u>Triangle DAB has b = 8, h = 8 and has area:</u>
- A = 1/2*8*8 = 32 sq. units
<u>Total area:</u>