<h3>20 subtracted from three times a number is 6 more than the number. Then the number is 13</h3>
<em><u>Solution:</u></em>
<em><u>Given statement is:</u></em>
20 subtracted from three times a number is 6 more than the number
We can translate the sentence into algebraic expression
Let "a" be the unknown number
Then,
20 subtracted from three times "a" is 6 more than "a"
Which means,
3a - 20 = 6 + a
3a - a = 6 + 20
2a = 26
Divide both sides by 2
a = 13
Thus the number is 13
2(b-5)+7b-4
Solve 2(b-5) to get 2b-10
Combine your like terms 2b-10+7b-4
Solve 2b+7b to get 9b
Solve -10+(-4) to get -14
So your answer is
9b-14
Answer:
There are both on the same side of the image "O and P"
If this dose not help please tell me!
Answer:
You got it! ill do it now
Step-by-step explanation: