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serious [3.7K]
3 years ago
6

∣6x−7∣−8≥3 PLEASE HELP ASAP!!!!!

Mathematics
2 answers:
gavmur [86]3 years ago
8 0

first step is to isolate the absolute value by adding 8 to each side

|6x-7| >= 11

now separate into 2 equations a positive and a negative (remembering to flip the inequality symbol for the negative)

6x-7>=11         6x-7<=-11

add 7 to each side

6x>=18       6x<=-4

divide by 6

x>=3           x<=-4/6

-2/3 >= x or 3<=x


Rufina [12.5K]3 years ago
7 0

Answer:

x \le -\dfrac{2}{3}   or   x \ge 3

Step-by-step explanation:

|6x - 7| - 8 \ge 3

|6x - 7| \ge 11

6x - 7 \le -11   or   6x - 7 \ge 11

6x \le -4   or   6x \ge 18

x \le \dfrac{-4}{6}   or   x \ge \dfrac{18}{6}

x \le -\dfrac{2}{3}   or   x \ge 3

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