Question

∣6x−7∣−8≥3 PLEASE HELP ASAP!!!!!

Answer 1

first step is to isolate the absolute value by adding 8 to each side

|6x-7| >= 11

now separate into 2 equations a positive and a negative (remembering to flip the inequality symbol for the negative)

6x-7>=11         6x-7<=-11

add 7 to each side

6x>=18       6x<=-4

divide by 6

x>=3           x<=-4/6

-2/3 >= x or 3<=x

Answer 2

Answer:

$x \le -\dfrac{2}{3}$   or   $x \ge 3$

Step-by-step explanation:

$|6x - 7| - 8 \ge 3$

$|6x - 7| \ge 11$

$6x - 7 \le -11$   or   $6x - 7 \ge 11$

$6x \le -4$   or   $6x \ge 18$

$x \le \dfrac{-4}{6}$   or   $x \ge \dfrac{18}{6}$

$x \le -\dfrac{2}{3}$   or   $x \ge 3$