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3 years ago

Line AB is rotated to form A'B'¯¯¯¯¯¯¯ .

Mathematics

2 answers:

sleet_krkn [62]3 years ago

6 0

I think the correct answer is A. Hope this helps.

drek231 [11]3 years ago

6 0

The answer is B. I just took the test.

I hope this helps! :)

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Rewrite the fraction 5 over 4 as an equivalent fraction with a denominator equal to 16

irakobra [83]

5/4=
20/16
Answer: 20/16

4 0

3 years ago

Read 2 more answers

Pleaseee help answer correctly !!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!

Alexeev081 [22]

Answer:

108º

Step-by-step explanation:

to find the sum of interior angles: ( n − 2 ) × 180 = x

x = 540º

n = # of interior angles

first, solve for n

(n - 2) • 180 = 540 distribute to 180 to (n - 2)

180n - 360 = 540 add 360 to both sides

180n = 900 divide both sides by 180

n = 5

to find measure of each angle:

540 ÷ 5 = 108º

5 0

3 years ago

Help me please. Rounding questions.

ehidna [41]

Step-by-step explanation:

a) 6400

b) 4800

c) 32000

hope this answer helps you dear!

3 0

3 years ago

Help me guys thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

Step 1: Multiply

$(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

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If -3x–7 =23 then 6x=?

vovangra [49]

Answer:

6x = -60

Step-by-step explanation:

-3x - 7 = 23

-3x = 30

x = -10

6(-10) = -60

8 0

3 years ago

Line AB is rotated to form ​ A'B'¯¯¯¯¯¯¯ ​.

Line AB is rotated to form A'B'¯¯¯¯¯¯¯ .