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Julli [10]
4 years ago
12

Kenny drew and cut out a angle that mesures 85 degrees beginning at the vertex he cut the angle into two angles one of the new a

ngles mesures 20 degrees what is the measure of the other new angle
Mathematics
2 answers:
Whitepunk [10]4 years ago
7 0
The measure of the new angle is 65 degrees 
Colt1911 [192]4 years ago
6 0
65 degrees is your answer
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The base and height of a triangle are each equal to the side length of a square.
marishachu [46]
If that's true then the area of the triangle is half as much as the area of the square.
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3 years ago
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What is the same value as 32 tens the picture blary I don't no why
Natalka [10]
The answer you are looking for is 320
7 0
4 years ago
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At Best Burgers, Jack collected sales data on the type of side order served with each type of burger purchased for a week. Jack
horsena [70]

The <em><u>correct answers</u></em> are:

60 pounds of onion rings and 60 hamburgers.

Explanation:

Jack serves a half pound of onion rings with every burger.  He serves 120 bacon cheeseburgers.  To find the number of pounds of onion rings, we multiply 1/2 pound by 120 burgers:

1/2(120) = 1/2(120/1) = (1*120)/(2*1) = 120/2 = 60 pounds of onion rings.

There were 8 hamburgers served out of the first 40 orders.  If this rate continues, then to find the number of hamburgers out of 300 orders, we multiply 8/40 by 300:

8/40(300) = 8/40(300/1) = (8*300)/(40*1) = 2400/40 = 60

There would be 60 hamburgers.

4 0
4 years ago
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The price of a computer was decreased by 10% to £504. What was the price before the decrease
katovenus [111]

Answer:

Step-by-step explanation:

100-10  :  100

90    : 100

504  : x

x=540x100/90

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x=560

7 0
3 years ago
Plz solve this question​
Mkey [24]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Simplify ⇨ 1/x(x+a) + 1/x(x-a)

\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}

\sf\frac { 1 } { x ( x + a ) } + \frac { 1 } { x ( x - a ) } \\

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x\left(x+a\right) and x\left(x-a\right) is x\left(x+a\right)\left(x-a\right). Multiply \frac{1}{x\left(x+a\right)} times \frac{x-a}{x-a}. Multiply \frac{1}{x\left(x-a\right)} times \frac{x+a}{x+a}.

\sf\frac{x-a}{x\left(x+a\right)\left(x-a\right)}+\frac{x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Because \frac{x-a}{x\left(x+a\right)\left(x-a\right)} and \frac{x+a}{x\left(x+a\right)\left(x-a\right)} have the same denominator, add them by adding their numerators.

\sf\frac{x-a+x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Combine like terms in x-a+x+a.

\sf\frac{2x}{x\left(x+a\right)\left(x-a\right)}  \\

Cancel out x in both the numerator and denominator.

\sf\frac{2}{\left(x+a\right)\left(x-a\right)}  \\

Expand \left(x+a\right)\left(x-a\right).

\boxed{\boxed{ \bf\frac{2}{x^{2}-a^{2}}}}  \\

3 0
3 years ago
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