The rate of change will be positive and a point in the graph will be (1,250);
the function then would be y = 250x;
after 1 year she will owe USD 5,250;
she will have to make 33 payments.
How to form equation using slope and one point?
y - y1 = m(x - x1) is the equation of a straight line's point slope form, where m is the line's slope and (x1, y1) is the point through which the provided line passes.
Using slope-point equation, the equation for the payment can be taken as:
y-250 = [(500-250)/(2-1)]*(x-1)
y - 250 = 250*(x-1)
y = 250 + 250x - 250 = 250x;
Putting x = 12, for a year the amount paid is USD 3,000.
Amount she owes = USD (8250-3000) = USD 5,250;
Total amount to be paid (in USD) = 8250
Amount paid per month (in USD) = 250
Thus, number of payments required = 8250/250 = 33
Thus, the rate of change will be positive and a point in the graph will be (1,250); the function then would be y = 250x; after 1 year she will owe USD 5,250; she will have to make 33 payments.
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Answer:
C, (x = 100, y = 10)
Step-by-step explanation:
hi again,
(2x - 70) = (x + 30), by the Alternate Exterior Angles
x - 70 = 30
<em>x = 100</em>
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(2x - 70) + 5y = 180, by the Linear Pair Theorem
2(100) - 70 + 5y = 180
200 - 70 + 5y = 180
130 + 5y = 180
5y = 50
<em>y = 10</em>
Answer:
(-1,-4)
Step-by-step explanation:
Using the rule of when we rotate 90 degrees clockwise
(x,y) goes to (y,-x). We plug it in.
(4,-1) goes to (-1,-4).
Quadratics always have 2 solutions, a positive and a negative version of the answer