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Lena [83]
2 years ago
12

Which subset(s) of numbers does 8 2/3 belong to?

Mathematics
1 answer:
Tems11 [23]2 years ago
7 0

Answer:

Rational number/integer

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Which relation is a function?<br> Question 3 options:
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Answer:

A function is a relation in which each input has only one output. In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y, because the input y = 3 has multiple outputs: x = 1 and x = 2.

I hope it's helpful!

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Using SET NOTATION, what is the solution set for the following equation? a² - 3 = 22
mixas84 [53]

Answer:

a = 5 or  a = -5

Step-by-step explanation:

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What is the range of the function y = -x2 + 1?
meriva
<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
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What power of 10 makes this expression equal to 30,000?<br><br><br>3 x 10
pickupchik [31]

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10x3000

Step-by-step explanation:

4 0
3 years ago
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Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the
tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

f(x)=4x^{2} -1

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

so

The axis of symmetry is x=0

Part 2) we have

g(x)=x^{2}-8x+5

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

g(x)-5=x^{2}-8x

g(x)-5+16=x^{2}-8x+16

g(x)+11=x^{2}-8x+16

g(x)+11=(x-4)^{2}

g(x)=(x-4)^{2}-11

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

so

The axis of symmetry is x=4

Part 3) we have

h(x)=-3x^{2}-12x+1

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

h(x)-1=-3x^{2}-12x

h(x)-1=-3(x^{2}+4x)

h(x)-1-12=-3(x^{2}+4x+4)

h(x)-13=-3(x+2)^{2}

h(x)=-3(x+2)^{2}+13

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

so

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

so

h(x),f(x),g(x)

7 0
3 years ago
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