Perform indicated operations for function: f(x)=x^2+1 use in f(x+h)-f(x)/h

1 answer:

5 0

For $f(x+h) - \dfrac{f(x)}{h}$ reading the fraction like f(x)/h only (f(x+h) start fraction f(x) / h end fraction), the answer is $-x^2/y + x^2 + 2x + y + y^2 - 1/y + 1$

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Please Help Me!!!! Max Points

Arada [10]

Answer:

P(5) = 1/3

Step-by-step explanation:

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P(5) = 1/3

8 0

2 years ago

Read 2 more answers

If f(x)=3-2xand g(x)= 1/x+5, what is the value of f/g (8)?

Eva8 [605]

Answer:

$-\frac{104}{41}$

Step-by-step explanation:

$\frac{f(x)}{g(x)}=\frac{3-2x}{\frac{1}{x} +5}$

To make this easier to deal with, we can plug in 8 first:

$\frac{f(8)}{g(8)}=\frac{3-2(8)}{\frac{1}{(8)}+5 }$
Then we can simplify the terms to get $\frac{3-16}{\frac{1}{8} +5}=\frac{-13}{\frac{1}{8} +5}$
The denominator of this fraction needs to have its own common denominator. To do so, we can multiply the 5 by $\frac{8}{8}$ to give us: $\frac{1}{8}+\frac{40}{8}$
We can then simplify this to $\frac{41}{8}$
Now putting this back into our original fraction we have: $\frac{-13}{\frac{41}{8} }$
This is also equivalent to $\frac{(\frac{-13}{1} )}{(\frac{41}{8} )}$ which means we need to take the whole denominator of the fraction and flip it and multiply it by the numerator to get: $\frac{-13}{1}*\frac{8}{41}$
This then simplifies to $\frac{-104}{41}$