The price of the small pots is $2.40 so you would have 2.4s ( multiply the number of small pots by the price)
She bought a total of 14 pots, so the number of large pots would be 14 - s ( subtract the number of small pots from the total )
Now you have:
L = 14-s
2.4s + 5.6(14-s) = 49.6
The answer is C.
Answer:
729
Step-by-step explanation:
Answer:
95% of monthly food expenditures are between $110 and $190.
Step-by-step explanation:
Given : The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. The sample mean is $150 and the standard deviation is $20.
To find : Using the Empirical rule, about 95% of the monthly food expenditures are between which of the following two amounts?
Solution :
At 95% of the data is between two standard deviation to left and right of the mean is given by,
To the left side, 
To the right side, 
We have given,
The sample mean 
The standard deviation 
Substitute in the formula,








Therefore, 95% of monthly food expenditures are between $110 and $190.
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4

For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)

For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)

Answer:
4/10
Step-by-step explanation:
take it or leave it