If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
Answer:
Step-by-step explanation:
The conjugate of a radical expression is obtained by changing the sign of the middle term.
The conjugate of 
is simply 
Therefore, to obtain the conjugate of the given expression we simply shall be changing the negative sign to positive;
The conjugate of 
is simply;
Answer:
y = 
x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 5) ← 2 points on the line
m = 
=
The line crosses the y- axis at (0, 2 ) ⇒ c = 2
y = x + 2 ← equation of line
The only one with two obtuse and two right angles.
Trapezoid
Answer:-23
Step-by-step explanation:
