HELP PLEASEEEEEEEEEEE

What is the range of the function represented by the graph?

mojhsa [17]

Answer:

{1,2,3,4}

Step-by-step explanation:

cant be zero, also got it right on edge 2020

8 0

3 years ago

Read 2 more answers

Anyone know how to work this out

Leona [35]

Answer:

The perimeter is 70

Step-by-step explanation:

Isosceles means all sides same length. So to start out, you need to firgure out x so you can do let's say 3x-5=19x, or you can do 2x=19-x, or an combination pretty much. Once completing this, you find that x=14. Now all you have to do is plug 14 into all the x spots, and add everything together

Hope it helped :-)

4 0

4 years ago

How do I find the horizontal asymptote of h(x)=x+6/x^2-64 ?

SashulF [63]

I assume the equation described is:

( x + 6 ) / ( x^2 - 64 )

You can compare the degree of the numerator and denominator in a function that takes the form of this type of rational equation.

Here are the three rules

#1 (Correct Answer): When the degree of the numerator is smaller then the denominator the horizontal asymptote is y = 0

#2 If the degree of the numerator and denominator is the same, then you take the leading coefficient of the numerator (n) and denominator (d) to create the answer y = n / d in this equations case it would be 1 / 1 since variables technically have an invisible 1 in front of them since anything multiplied by 1 is its self, 1x = x

#3 When the degree of the numerator is greater then the degree of the denominator then this means that it does not have a horizontal asymptote.

Again the final answer is that the horizontal asymptote is y = 0

5 0

3 years ago

PLLLLZZSSZ HELPPP i really need to finish

Andrews [41]

Answer:

Step-by-step explanation:

Equation of the function is,

f(x) = 2x² + 20x + 54

To convert the function in the form of f(x) = a(x - h)² + k

f(x) = 2(x² + 10x) + 54

= 2[x² + 2(5x) + 25 - 25] + 54

= 2[x² + 2(5x) + 5²] + 54 - 50

= 2(x + 5)² + 4

= 2[(x - (-5)]² + 4

Vertex of the quadratic equation (parabola) will be (-5, 4)

Therefore, f(x) has a minimum value at x = -5,

f(-5) = 4

"The function f(x) has a minimum value of 4, which occurs when x = 5"

3 0

3 years ago

Please help me with 7 and 9 I’m really confused and I really need help!!

Margarita [4]

Answer:

7) K'(1, 1), N'(4, 0), Q'(4, 4)

9) F'(4, 2), W'(4, 5), K'(3, 2)

Step-by-step explanation:

When you are not sure about reflections and rotations, it can be useful to actually draw a graph. The line of reflection is the perpendicular bisector of the segment connecting a point with its image. That is, the image is the same distance from the line on the other side. A point that is <em>on</em> the line of reflection is "invariant," it doesn't move.

__

7) Reflecting across the x-axis changes the sign of the y-coordinate. That is all. Any point on the x-axis (y=0) is unchanged. The transformation is ...

(x, y) ⇒ (x, -y)

__

9) Reflecting across a vertical line changes the x-coordinate. The new value of x will be ...

x' = 6 - x

The "6" is double the x-coordinate of the vertical line. The transformation is ...

(x, y) ⇒ (6-x, y)

_____

<em>Derivation of the formula for reflection on x=3</em>

In general if M is the midpoint of a point (A) and its reflection (A'), then we have ...

M = (A +A')/2

2M = A + A'

2M -A = A'

When a point is reflected across a vertical line, all of the y-coordinate values remain unchanged. So, for A=(x, y) and M=(3, y), we have ...

A' = 2(3, y) -(x, y) = (6-x, 2y-y)

A' = (6 -x, y)

So, the reflection transformation across the line x = 3 is ...

(x, y) ⇒ (6-x, y)

6 0

3 years ago