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4 years ago

How do you spell 80 in word form

Mathematics

2 answers:

labwork [276]4 years ago

6 0

80 in word form

Eighty

Hope this helped!

Fiesta28 [93]4 years ago

6 0

80 in word form is eighty

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Please help me with this question

lilavasa [31]

Y^2 - (y+5)^2 = 20
starting with (y+5)^2 that's y^2 + 5y + 5y + 25
then you change the signs and get
y^2 - y^2 - 10y - 25 = 20
so -10y = 45 >> 10y = -45 >> y = -4,5
answer: A

6 0

3 years ago

Read 2 more answers

(10 - 2 )^{2} + ( 5 - 10 ÷ 2 )

bixtya [17]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

(10 - 2)² + (5 - 10 ÷ 2)

Step 2: Evaluate

(Parenthesis) Divide: (10 - 2)² + (5 - 5)
(Parenthesis) Subtract: 8²
Exponents: 64

8 0

3 years ago

Read 2 more answers

Unit 3 | Lesson 9

Andrei [34K]

P = 6s
s = 3.4

P = 6(3.4) = 20.4 cm

3 0

3 years ago

Read 2 more answers

Volume of cylinder with a radius of 8cm and height of 25 cm

Anarel [89]

Answer:

V≈5026.55 cm³ is the exact answer! If you need to use only 3.14 for π then 5024 cm³

Step-by-step explanation:

7 0

3 years ago

Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola

k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

$b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55$

General equation of hyperbola is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1$

Hence, this is the required solution.

3 0

3 years ago