Question

Please explain your answer. Thank you.

Answer 1

Answer:

17. The median of trapezoid = 10 units

m<A = 68°

18. ΔABC ≅ ΔADC

Step-by-step explanation:

17). To find the median of trapezoid

From the figure we can see a trapezoid ABCD.

Median of trapezoid = Half the sum of bases

Here base of trapezoid are 15 and 5 units

Median = (15 + 5)/2 = 10

Also it is given that ABCD is isosceles trapezoid,

Therefore m<A =m < B = 68°

18). To prove  ΔABC ≅ ΔADC

From the second figure we can see two triangles  ΔABC and ΔADC

It is given that,

<BCA = <ACD

<B = <D = 90°

From figure we can see that, AC is common for both the triangle.

Therefore by HL congruence we can see that,  ΔABC ≅ ΔADC