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kondaur [170]
3 years ago
15

Please explain your answer. Thank you.

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

17. The median of trapezoid = 10 units

m<A = 68°

18. ΔABC ≅ ΔADC

Step-by-step explanation:

<u>17). To find the median of trapezoid</u>

From the figure we can see a trapezoid ABCD.

Median of trapezoid = Half the sum of bases

Here base of trapezoid are 15 and 5 units

Median = (15 + 5)/2 = 10

Also it is given that ABCD is isosceles trapezoid,

Therefore m<A =m < B = 68°

<u> 18). To prove  ΔABC ≅ ΔADC</u>

From the second figure we can see two triangles  ΔABC and ΔADC

It is given that,

<BCA = <ACD

<B = <D = 90°

From figure we can see that, AC is common for both the triangle.

Therefore by HL congruence we can see that,  ΔABC ≅ ΔADC

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m=\frac{2506.833}{604.833}=4.1447  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{77}{6}=12.833  

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And we can find the intercept using this:  

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Step-by-step explanation:

m=\frac{S_{xy}}{S_{xx}}  

Σx = 77, Σy = 587, Σx2 = 1593, Σy2 = 70,533, and Σxy = 10040.

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=1593-\frac{77^2}{6}=604.833  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=10040-\frac{77*587}{6}=2506.833  

And the slope would be:  

m=\frac{2506.833}{604.833}=4.1447  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{77}{6}=12.833  

\bar y= \frac{\sum y_i}{n}=\frac{587}{6}=97.833  

And we can find the intercept using this:  

b=\bar y -m \bar x=97.833-(4.1447*12.833)=44.644  

So the line would be given by:  

y=4.1447 x +44.644  

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