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Naddik [55]
3 years ago
9

Why is the percent increase from 45 to 75 not equal to the percent decrease from 75 to 452 Select three options

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0

Answer:the ratio of the % increase has a different numerator from decrease

Step-by-step explanation:

velikii [3]3 years ago
5 0

Answer:

2,3,5

that is the answer

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In our class, there are 14 female and 11 male students. a. Pick one student randomly, what is the probability you get a female s
Reika [66]

Answer:

a) 56% probability you get a female student.

b) 30.33% probability that both are female

c) 43.52% probability that you get 2 female and one male

d) 18.26% probability that you get 1 female and 3 male

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in whih the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

a. Pick one student randomly, what is the probability you get a female student?

Desired outcomes:

1 female student from a set of 14. So

D = C_{14,1} = \frac{14!}{1!13!} = 14

Total outcomes:

1 student from a set of 25. So

T = C_{25,1} = \frac{25!}{1!24!} = 25

Probability:

P = \frac{D}{T} = \frac{14}{25} = 0.56

56% probability you get a female student.

b. Pick two students randomly, what is the probability that both are female?

Desired outcomes:

2 female students, from a set of 14. So

D = C_{14,2} = \frac{14!}{2!12!} = 91

Total outcomes:

2 students from a set of 25. So

T = C_{25,2} = \frac{25!}{2!23!} = 300

Probability:

P = \frac{D}{T} = \frac{91}{300} = 0.3033

30.33% probability that both are female

c. Pick three students randomly, what is the probability that you get 2 female and one male?

Desired outcomes:

2 female students, from a set of 14, and one male student, from a set of 11. So

D = C_{14,2}*C_{11,1} = \frac{14!}{2!12!}*\frac{11!}{1!10!} = 1001

Total outcomes:

3 students from a set of 25. So

T = C_{25,3} = \frac{25!}{3!22!} = 2300

Probability:

P = \frac{D}{T} = \frac{1001}{2300} = 0.4352

43.52% probability that you get 2 female and one male

d. Pick four students randomly, what is the probability that you get 1 female and 3 male?

Desired outcomes:

1 female student, from a set of 14, and 3 male students, from a set of 11.

D = C_{14,1}*C_{11,3} = \frac{14!}{1!13!}*\frac{11!}{8!3!} = 2310

Total outcomes:

4 students from a set of 25. So

T = C_{25,4} = \frac{25!}{4!21!} = 12650

Probability:

P = \frac{D}{T} = \frac{2310}{12650} = 0.1826

18.26% probability that you get 1 female and 3 male

5 0
3 years ago
Which expression below is equivalent to 2x + 8?
mash [69]

Answer: D) x+4+x+4

The two x terms combine to x+x = 2x

The other pair of like terms, the constants, add to 4+4 = 8

Overall we get 2x+8

2x+8 is also equivalent to 2(x+4) when you factor out the GCF 2.

7 0
2 years ago
Gideon wants to buy a new video game from the store. They are having a sale on all games, and sell the game at a 15% discount. H
marta [7]

Answer:

5%+15%=20%

to find 20% of 28 u multiply 28 x 0.2= 5.6

so to remove the 20% since it's 20% off u subtract 5.6 from 28

28-5.6= 22.4

Step-by-step explanation:

4 0
2 years ago
Is #4 correct, if not what is
svet-max [94.6K]
Number 4 is correct a^0=1 for all real number a
number 5
y^2(y^2=y^(2+2)=y^4 correct
y^6/y^2=y^(6-2)=y^4 correct
y^0=1 false
y^9/y^5=y^(9-5)=y^4 correct
y^4(y^1)=y^(4+1)=y^5 false
4 0
3 years ago
Read 2 more answers
Choose all the ones
ElenaW [278]

Answer:

A, C, D

Step-by-step explanation:

A. $5.60 per class

$196 divided by 35

B. $6.50 per class

$260 divided by 40

C. $5.00 per class

$250 divided by 50

D. $5.50 per class

$55 divided by 10

E. $7.60 per class

$342 divided by 45

8 0
2 years ago
Read 2 more answers
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