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12345 [234]
3 years ago
9

How do you graph 3x-2y<-4

Mathematics
1 answer:
sveta [45]3 years ago
4 0
The slope-intercept form is
y
=
m
x
+
b
y
=
m
x
+
b
, where
m
m
is the slope and
b
b
is the y-intercept.
y
=
m
x
+
b
y
=
m
x
+
b
Find the values of
m
m
and
b
b
using the form
y
=
m
x
+
b
y
=
m
x
+
b
.
m
=
3
2
m
=
3
2
b
=
−
2
b
=
-
2
The slope of the line is the value of
m
m
, and the y-intercept is the value of
b
b
.
Slope:
3
2
3
2
Y-Intercept:
−
2

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3 0
3 years ago
I have no idea what the answers are
lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
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