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12345 [234]
2 years ago
9

How do you graph 3x-2y<-4

Mathematics
1 answer:
sveta [45]2 years ago
4 0
The slope-intercept form is
y
=
m
x
+
b
y
=
m
x
+
b
, where
m
m
is the slope and
b
b
is the y-intercept.
y
=
m
x
+
b
y
=
m
x
+
b
Find the values of
m
m
and
b
b
using the form
y
=
m
x
+
b
y
=
m
x
+
b
.
m
=
3
2
m
=
3
2
b
=
−
2
b
=
-
2
The slope of the line is the value of
m
m
, and the y-intercept is the value of
b
b
.
Slope:
3
2
3
2
Y-Intercept:
−
2

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The points (4, -11) and (8, r) lie on a line with slope 2. Find the missing coordinate r.
WINSTONCH [101]

Answer:

The answer to your question is r = -3

Step-by-step explanation:

Data

A (4, -11)

B (8, r)

slope = m = 2

r = ?

Process

1.- Use the slope equation to find the coordinate r.

Formula

               m = \frac{y2 - y1}{x2 - x1}

Substitution

        m = \frac{r + 11}{8 - 4} = 2

2.- Simplify

                \frac{r + 11}{4} = 2

3.- Solve for r

Multiply both sides by 4

               \frac{4(r + 11)}{4} = 2(4)

Simplify

                r + 11 = 8

Subtract 11 in both sides

                r + 11 - 11 = 8 - 11

Simplify

                r = -3

       

7 0
3 years ago
Determine the function which corresponds to the given graph<br> The asymptote is x=3
stepladder [879]
The function has a horizontal asymptote at y = 3.
The function has a vertical asymptote at x = -3.
The function has a  vertical intercept of 1.
The function has a zero of x = -2.

Because the function has a zero at x = -2, and a vertical asymptote at x = -3, therefore
y= \frac{k(x+2)}{x+3}

Write the function in the form
y = y= \frac{k(1+ \frac{2}{x}) }{1+ \frac{3}{x} }

As x → ∞, y → k.
Because a horizontal asymptote exists at y = 3, therefore  k = 3.
A vertical intercept exists at y = 1.
The function is
 y =  \frac{3(x+2)(x+1)}{(x+3)(x+1)}

Answer: y =  \frac{3(x+2)(x+1)}{(x+3)(x+1)}


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