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KATRIN_1 [288]
3 years ago
12

How many times does 31 go into 248?

Mathematics
1 answer:
valina [46]3 years ago
5 0
248 / 31 = 217 times
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Andrew rents bowling shoes for $4. He bowls 2 games. Andrew spent a total of $22. How much was the cost of each game, b? Complet
Aneli [31]

Answer:

2b + 4 = 22

b= 9, the cost of each game is $9

Step-by-step explanation:

8 0
3 years ago
Help!! Which of the following best represents Z1 • Z2 select all that apply
AURORKA [14]

z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)

z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}

\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\

Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)

On simplifying, we get

Z_1* Z_2 =-3\sqrt{2}

<h2>Therefore, correct option is  1st option.</h2>
3 0
3 years ago
I need help with number 2!! please help!
Maurinko [17]

Answer:

12.68

Step-by-step explanation:

76 degrees /2 = 38

Half the width of 15m forms the lower side of the triangle: 7.5 m

sin(38) = 7.5/h

=12.1820

12.18+.5

12.68

5 0
3 years ago
Find the unknown length x in the right triangle, to the nearest tenth.<br> 16<br> 21
PIT_PIT [208]

Answer:

16 rounded to the nearest 10 is 20

21 rounded to the nearest 10 is 20

so I don't really know but I guess you should put the x as 20 for sure UwU

3 0
2 years ago
To input your angle measures in degrees, use the functions sind, cosd and tand, instead of sin, cos and tan. Zach stands at the
kramer

Answer:

  about 2949 feet

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...

  Tan = Opposite/Adjacent

__

<h3>setup</h3>

Filling in the known values, we have ...

  tan(6°) = (310 ft)/(distance to coyote)

<h3>solution</h3>

Multiplying by (distance to coyote)/tan(6°) gives ...

  distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft

  distance to coyote ≈ 2949.453 ft

The coyote is about 2949 feet from the base of the cliff.

6 0
2 years ago
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