Find the variable<br> 1) 3x +25= 2x

I REALLY NEED HELP PLEASE ANSWER THIS QUESTION RIGHT NOOOO SCAMS

notsponge [240]

Answer:

x = 49

Step-by-step explanation:

3x - 33 = 2x + 16

subtract 2x from both sides: x - 33 = 16

add 33 to both sides: x = 49

5 0

3 years ago

The equation cos(x)( cos(x)-tan(x)sin(x)) simplifies to

sashaice [31]

I am sorry but I do not know but if someone else know help

6 0

3 years ago

As a candle burns, it decreases in height by 2 inches every hour. If the candle is 12 inches tall when it is lit, how will the h

Nadya [2.5K]

y=-2x+12

y = the height of the candle in inches

x = the amount of time the candle burns

the height decreases 2 inches each hour so over by the first hour the candle will be 10 inches tall and so on

8 0

3 years ago

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Four rats are selected at random from a cage of 5 male (M) and 6 female (F) rats. If the random variable Y is concerned with the

Ludmilka [50]

Using the hypergeometric distribution, it is found that the distribution is:

P(X = 0) = 0.0152

P(X = 1) = 0.1818

P(X = 2) = 0.4545

P(X = 3) = 0.3030

P(X = 4) = 0.0455

Hence:

A) There is a 0.0455 = 4.55% probability that all selected rats are female.

B) There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

C) There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

D) The mean of the probability distribution is of 2.18.

E) The standard deviation of the probability distribution is of 0.833.

The rats are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There is a total of 11 rats, hence N = 11.

6 of the rats are female, hence k = 6.

4 rats are taken, hence n = 4.

The distribution is the probability of each outcome, hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,11,4,6) = \frac{C_{6,0}C_{5,4}}{C_{11,4}} = 0.0152$

$P(X = 1) = h(1,11,4,6) = \frac{C_{6,1}C_{5,3}}{C_{11,4}} = 0.1818$

$P(X = 2) = h(2,11,4,6) = \frac{C_{6,2}C_{5,2}}{C_{11,4}} = 0.4545$

$P(X = 3) = h(3,11,4,6) = \frac{C_{6,3}C_{5,1}}{C_{11,4}} = 0.3030$

$P(X = 4) = h(4,11,4,6) = \frac{C_{6,4}C_{5,0}}{C_{11,4}} = 0.0455$

Item a:

P(X = 4) = 0.0455, hence:

There is a 0.0455 = 4.55% probability that all selected rats are female.

Item b:

P(X = 1) = 0.1818, hence:

There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

Item c:

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.4545 + 0.3030 + 0.0455 = 0.803$

There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

Item d:

The mean of the hypergeometric distribution is:

$\mu = \frac{nk}{N}$

Hence:

$\mu = \frac{4(6)}{11} = 2.18$

The mean of the probability distribution is of 2.18.

Item e:

The standard deviation of the hypergeometric distribution is:

$\sigma = \sqrt{\frac{nk(N-k)(N-n)}{N^2(N-1)}}$

Hence:

$\sigma = \sqrt{\frac{4(6)(11-6)(11-4)}{11^2(11-1)}} = 0.833$

The standard deviation of the probability distribution is of 0.833.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

5 0

2 years ago

there is approximately 4.5 million births in a country each year. Find the birth rate of births per minute.

Flauer [41]

It’s simple you divide so 4,500,000 divided by 365 then divide that by 60

7 0

4 years ago

Find the variable 1) 3x +25= 2x